On the Annual Water-discharge of Large Rivers. 267 
Horizontal Distance 
poate Depth. from last Station. 
0° 0-00 feet. 0 feet. 
1 12:33 ,, tge0- 2 
2 24:42 ,, Sines, 
3 73:10- 110. 2 
4 59-10 750 ,, 
5 37°75 ,, 1980 ,, 
6 O00 5; 960 ,, 
The first and last of these sections are triangles, and the others 
are trapezia. The areas and hydrostatic pressures of the several 
sections are given in the following Table :— 
Section. Area. Product, Ayl. 
O2stonle 5303 sq. feet. 21,790 cub. ft. 
17. 2 1782 +0 16,994 ,, 
ae Le ae 141,626 ,, 
y  € 69575 ,, 1,269,760 ,, 
5-5 95880, 2,357,550 4, 
5 6 18120 ,, 228,015 ,, 
WIS 82) F3, 4,035,735 yy 
In order to find the discharge, we must multiply the total 
hydrostatic pressure by 2k, from equation (2), and divide by 60, - 
to reduce to cubic feet per second. This gives us 
4,035,735 x 8-6067 
eres G0) ae 
=078,910 cubic feet per second, 
which agrees with Mr. Bateman’s minimum result for December, 
viz., 520,000 cubic feet per second. | 
The water-discharge of the Uruguay on the 3rd February, 
1871, may be thus found :— 
(TABLE, 
