284 



Mr Vegard, On some general Properties 



3. We choose one of the components, e.g., the first one as the 

 principal component, and we express the concentrations of the 

 others by the ratio between their masses and that of the principal 

 component, all masses being united in the same volume element, 

 or 



C, 



a 



a. 



We have 



s = l,2 



Forming the expression in equation (23) and putting 



qip-l = ai, 

 we get the following system 



(25) I'M^^^a,^. 

 s=i dCs dx ^ dx ' 



i=0,l,2 ...r. 



In this case there are only r concentrations, and consequently 

 r unknown. If we drop the first of the (r + 1) equations (25), we 

 get the following solution 



(26) 



9ci 9c2 " ' dci ' ' ' dcr 



dAdf^df^jf, 



dci dc^'" dci ' ' ' dCr 

 8ci dCo'" dCi ' ' ' dC). 



'dfr dfv dfr 



9ci 9c2 " ' dCi 



dfr 

 dCr 



dci 

 dx 



dU 

 dx 



9ci 9c2 ' " * 9ci_i ^ 9ci+i ' ' " dCr 



dCx dCo" 9C;_i " dCi+i ' ' ' dCr 



dci_ dCo'" dci-i ^ dCi+i ' ' ' dc,. 



dfr dfr 



dfr dfr 



CLr 



C/ r 



dci 9c2 ' " 9ci_i dci+i ' ' ' dCr 



dci 

 dx 



To find ^Nve must know the r quantities ai,a.2... oir, and, 



besides, a number of quantities derived from the thermodynamic 

 potentials. As we have 



dCs dci ' 



(27) 



