550 



MENDIZABAL TAMBORREL 



a — b — 4 m .8608 

 a-f 6 = 13 m .4844 



log cot - : 



0.633028 



log tan 



A—B 



= 0.189904 



A = 134° 2'27".7 

 B = 19°44 / 58 // .3 

 C= 26 o 12'34".0 

 180° 0' 0" 



Segundo Caso. — Se dan: 



a = 26 m .1213 



A = 42° 26a W 



B = 24°15' 6" 



A + B = 66°41'19" 



C = 113°18 / 41 // 



log sen B = 1.613573 



log a = 1.416995 



cp l log sen A = 0.170839 



log sen C = 1.966205 



log b =1.201407 

 6 = 15 m .901 

 c = 35 m .813 



log c= 1.554039 



Tercer Caso. — Se dan: 



a = 3 m .41 



6 = 2 .60 



c = l .58 



2jp = 7 .59 



^ = 3 .795 



p— a=0 .385 



p — 6 = 1 .195 



p — c = 2 .215 



log (p— a) = 1.58546 



log (p—b) ¡ = 0.07737 



log lp — c) = 0.34537 



0.00820 



logjo = 0.57921 



log w2 = 9.42899 



log iv = 9.71450 



A = 106°46'4O" 

 B= 46°53'14" 

 C= 26°20' 6" 



log tan- =0.12903 



A 



log tan -=1.63713 



n 



log tan - = 1.36912 



A 



4 = 63°23'20" 

 ?=23°26 / 37' / 



c 



i3°io' z» 



90° / 0" 



Cuarto Caso. — Se dan: 



a= 444 m .44 



6 = 1047 .00 



A = 22° 35' 48" 



log 6 =3.019947 

 log sen A =1.584 604 

 cp¿loga= 7.352187 

 log sen B = 1.956738 



B = 115° 8'55" 

 C= 42°15'16 // .3 



log a = 2.647813 



log sen C = 1.827644 



cp l log sen A = 0.415396 



log c = 2.890853 



(? = 777.73 



