ÖFVERSIGT AF K. VETENSK.-AKAD. FÖRHANDLINGAR 1902, N:0 9. olo 



Efter att ha anbragt vikterna på vanligt sätt kom jag då 

 till följande villkorsekvationer: 



X y z ti v 10 



[1.12381]=+[0.38023] + [0.05286]~[0.06593]+[0.17145] — [9.14301] — [9.24042] 

 [1.50894]= +[0.46437] + [0.13686] — [0.16132] + [0.25613] — [9.23242] — [9.34094] 

 [1.58249]= +[0.57055] + [0.24287] — [0.27675] + [0.36300] — [9.34313] — [9.46333] 

 [0.86627]= +[0.17563] + [9.84635] — [9.86394] + [9.97627] — [8.95042] — [9.15060] 

 [0.73588]= +[0.15954] + [9.82949] — [9.80899] + [9.96370] — [8.92521] — [9.14945] 



— [1.12595]= +[9.32681] + [9.02351] — [9.91586] + [9.00062] + [0.17652] + [0.27394] 



— [0.81834]= +[9.41554] + [9.11434]— [0.03705] t[9.08070] + [0.25455] + [0.36308] 



— [1.07212]= +[9.52501] + [9.22602] — [0.17719] + [9.18177] 4- [0.35433] + [0.47452] 



— [0.96379]= +[9.11892] + [8.83412] — [9.92274] + [8.73565] + [9.91476] + [0.11493] 



— [1.26007]= + [9.09081] + [8.80996] — [9.92696] + [8 70159] + [9.88438] + [0.10862] 



Sedan jag upplöst dessa med användande af minsta kvadrat- 

 metoden erhöll jag för x^ y, z, u, v, ic värdena: 



X = [2.07555 ] 



^ ==[1.41354 ] 



z =[1.13166„] 



u = [2.49720„] 



v = [2.29062 ] 



w = [2.3402 1„] 



Häraf fäs ändringarna i elementen: 



dMo = + 9".8 



dco = — 57 .9 



dn ^ + 2'59 .5 



di = + 451 .7 



dep =—2 1 .8 



d.f.1 = — 5 .136 



Det nya elementsystemet blir då följande: 



Epok 1897 nov. 24.5. Berl. medeltid. 



i/o 39^ 3'25".6 



w 144 16 56 .51 



-Q 220 43 50 .l| 1900.0 



i 9 55 40 .7) 



(p 8 22 29 .6 



IX 837".264 



a 0.4180961 



