E. - ■£- (X6+?) = tan 6 



1 dp p=p 1 



5 = (A6+£) - p. tan 6 

 o p=p 1 H l 



If X = p tan $ is assumed to be a constant in interval Ap, all the integration with 

 respect to p can be performed analytically in the interval both on the blade and in 

 the wake. 

 That is, by substituting Equation (34-1) in B 



where 



/ 



Ar dp = P(n+1) 



2 1/2 



B = (ap +2bp+c) 



2 

 a = 1 + tan 



b = - {r cos (<j)+6 k -6) + (x-£ ) tan 6} 



2 2 

 c = r + (x-£ ) 



ac-b 



P(2) .^i_iP±c 

 ac-b 



""-i li '(f") t ' a IX 



a \ /a / a (ac-b ) B 



14 



