The corrections given here are derived for structures with steep 

 slopes. Scale corrections for flatter slopes would be expected to 

 diminish in a manner similar to that for smooth slopes (Fig. 50), but 

 the correction factor of 1.0 might well be reached for some slope on 

 the order of cot 6=5 (or even steeper) . 



5. Example Problems . 



************* EXAMPLE PROBLEM 12 ************* 



GIVEN : Runup, uncorrected for scale effects, was determined in example 

 problem 4 for the following conditions: smooth structure slope; 

 cot 6=3; cot B = 90; H = 2.5 meters at d = 10 meters; T = 8 

 seconds; d s = 7.5 meters. Then, R/H^ =2.0 and R = 5.4 meters. 



Find : Determine the full-scale runup. 



SOLUTION : From Figure 50, for a structure slope of cot 6=3, the run- 

 up correction factor, k, is determined to be 1.12. The corrected 

 relative runup is then 



£r = (2.0)(1.12) = 2.24 

 n o 



and 



R = (2.24) (H^) 



R = (2.24) (2.68) = 6.0 meters . 



The correction factor, k, may also be applied directly to the 

 uncorrected absolute value of runup, R; then, 



R = (5.4) (k) 



R = (5.4) (1.12) = 6.0 meters . 



************************************ 



************* EXAMPLE PROBLEM 13 



************* 



GIVEN : Relative runup has been determined for a rubble-mound structure 

 which has quarrystone armor units. The top elevation of the core 

 is below SWL. Structure slope is cot 6 = 2; B = 0. R/H^ is based 

 on model experiments for R g « 1.3 x 10°. 



FIND: Determine the appropriate scale-effect correction factor, k. 



18 



