T = (20 x 60) = 2 400 seconds (40 minutes) 

 1 0.5 



co„ = 0.5 oj 



T =' T, = 2,400 seconds 



(N = 0, N 2 = 1) u = 0.366 m = 0.366 — 



_ T 20 x 60 



1 0.366 0.366 



T = 3,280 seconds (54.6 minutes) 



T__ _ 20 x 60 

 2 " 0.634 " 0.634 



T = 1,893 seconds (31.5 minutes) 



(N x = 0, N 2 = 2) oo 1 = .0.309 to 



= r T 20 x 60 



1 0.309 0.309 



Tj = 3,880 seconds (64.7 minutes) 



20 x 60 



2 ~ 0.691 0.691 



T 



T = 1,737 seconds (28.9 minutes) 



The wavelength of the first edge wave pair is given by equation (213) 

 where n = 0(N 1 = 0, N 2 = 0) , 



2tt_ (il\ 2 1 



V = L y = V,T / g(2n + 1) U 



= (-2L-Y l 



y \2,400/ 9.807(1) 0.001 



rs (5.6 miles) for both edge 



For the second edge wave pair, Nj = for u^ and N 2 = 1 for 



k u = l^—f = 3.74 x 10 ^ 



y \3,280/ 9.807(1) 0.001 



:an £ 



, = (-2LJ\ 2 1 : : 



\2',4'( 



and Lj. = 8,990 meters (5.6 miles) for both edge waves. 



105 



