From Table C-1 in the SPM, 



Therefore, 



K = iL « 0.9162 . 



H' = — = — ^ = 9.82 feet (3.0 meters) 



° Kg 0.9162 



d 



= 1.018 « 1.0 , 



S _ 10 



9.82 



and 



9.82 



0.00377 



gT2 (32.2) (9)2 



Because there is a steeply sloping bottom fronting the structure, 

 the value of £/L must be determined: 



£ = (50 - 10) (10) = 400 feet (122 meters) . 



Next determine the wavelength in water depth of 50 feet 

 (the depth at the toe of the 1 on 10 slope). For 



^ ^° 0.12045 , 



L^ (32.2/27T)(9)' 



and from Table C-1, 



- ~ 0.1585 . 

 L 



Therefore, 



L = — - = —— — = 315.46 feet (96.1 meters) 

 d/L 0.1585 



28 



