t. 



J 



As. 

 J 



t. 



J 



As. 

 1 



t. 



T 2 



j2 jl 



Lj3 Ljl 



As. 

 J 



t. 

 J 



As. 

 J 



t. 

 J 



As.. 



jl J2 



T 2 



^j3 Lj2 



As. 



L. 

 J 



t. 



As^ 

 t. 





~ 



L 



lL,3 



L 



ihs 



L 



3 









-294.20 



287.14 

 395.80 



im) m (2S)\ 



<J s @ @ (g) 



N 



As. 

 J 



t. 

 J 



t. 

 J 



As. 

 J 



t. 



Ipart j 



'part j 



the solution < K„ > , obtained by matrix inversion and multiplication, as 



U3J 



indicated in Sheet 2 of Table 4. 



Q^^ is obtained in a manner similar to that for finding Q^ as shown on Sheet 2 of 

 Table 4. The ZZ Flexibility is calculated at the right of Sheet 2; see Equations [46]— [48] 

 of Appendix A. 2 and pages 84-85. The y-shear center is calculated by Equations [34] of 

 Appendix A. 2. 



The solutions for torque involve the same loops as for z-shear; however, there is no 

 particular solution due to q because when V =V =0, q . = Oat each node; see page 

 76 of Appendix A. 2. The solution for Kj, K2, and K3 is now shown. (Refer also to Appendix 

 A. 2, Equation [37].) 



138.30 - 97.! 



132.88 

 52.80 



67.12 



-52.80 



99.64 



^®©' 5:(D'0® S(D®(6) 



= ^©Ci^'® S(D (5)2 5;(3)(5) (6) 

 S(D®(6) 2(D(5)® S(3)©2 



S(2)0| p:(RAs). L., 



1(2) (4 -h (RAs). L.2 ;. =^ 



S © (DJ [1 (RAs). L.3 



Area Loop 1"^ (Entries are identical to 



I those in the previous 



Area Loop 2 > ^^^^rix) 



^rea Loop 3j 



41 



