SOLUTION: 



From SPM Table C-1 (U.S. Army, 



rn Determine friction coefficient. -- 1Q77^ for 



corps of Engineers. Coastal Engineering Research Center. 1977) for 



(d/Lo)620 = 0-115. 



= 0.154 and L.oQ = ^^^'^ °^^'^^' 



620 



Using linear theory, 



^s620 



2.0 



A = 



=0.89 meter 



2 sinh kd 2(1.126) 



""b T sinh kd 10(1.126) 



From equation (4), 



R„ = 



% A (0. 56)(0.89) 

 (6.25 X lO"'^) 



,3 X 10- 



0.89 



k„ 2dQn 0-0006 



= 1.483 



'90 



Figure 2 then yields the friction 



coefficient at gage 620 to be 



Cj = 0.004 



(2) Determine predicted wave he 



is 14 meters: 



d _ 14 ^ _14 



T 100 



ight. The average depth in the travers 

 = 0.14 



(10)' 



From Figure 1 . 



— <|, = 0.180 or <j) = 1-29 

 ^2 



The bot 



n, is (8 0/2 200) = 0.0036. and the shoaling coefficient 

 i. .e;:r:in:d°^a:'ga:; 610 ^Lri^^he Le height is unknown: 



-1/2 



K„ = 



;610 



(tanhi^) 1. 



4iid 

 L 



sinh 



4iTd 



(0.591) 1 + 



-1. 



.360\ /2 



1.819 



= 0.984 



13 



