Pi = I p g Hf ci ni = -I (1026) (9.81) (3.5)2 10^ (0.757) 



= 1.33 • 10^ kilogram-meter per second cubed 

 Since d^ =-^^ = ^ (9) (18)" = 12.73 meters 



£m ^ (27r) (12.73) . ^ 

 T 9.81 (9.3)2 u-"^^^/ 

 o 



and Table C-1 gives (dm/Im) = 0.1360, sinh (2Trdn,/Lm) = 0.9621, (Hn,/H<i) = 

 0.9378 = Ksm, and n^ = 0.8199. Thus, % = (H, Kg^^/K^^) = (3.5) (0.9378)/ 

 (0.9160)= 3.58 meters and according to equation (9), 



Hjj 3.58 , », 



^ = 7T;^\^ 2(0.9621) = ^-^^ '"^'^" 



2 sinhf 



/ 2TTd„^ \ 



With Dm = 0.12 millimeter, equation (8) is 



fem = exp [-5.882 + 14.57 (Dm/Sm) °' ^^'^l 



= exp [-5.882 + 14.57 (1.2 ♦ 10"'*/1.86) " • l^**] = 0.0262 

 so that equation (7) becomes 



Em = 0.235 p fem( 



= 12.5 kilograms per second cubed 



h^Y = (0.235) (1026) (0.0262) [^^^^3^^^ 1 



Some conditions must also be computed at d^ = 9 meters, where 



di (2Tr) 9 



—J- = = 0.06665 



Lq (9.81) (9.3) 2 



so that Table C-1 gives (Hj/H^) = 0.9779 = Kg j , nj = 0.8688, and (dj/Lj) = 

 0.1108 so that Lj = 81.2 meters. Finally, because d^ < d^ the lower sign 

 in equation (10) is appropriate, and X = 1800 meters yields 



„2 ^^^1 ~V> 8[1.33 • 10^ - (12.5)(1800)] ,, „ 



Hf = = — = — i ^-i = 11.58 square meters 



J p g cj n-j (1026) (9.81) ^l /^ (0.8688) 



Hj = 3.40 meters 



From equation (11) , maximum water depth for bed agitation is da = 

 HiTl(g/5000D)0-5 = (3.5) (9.3) [9.81/(5 • 103)(0.12 • 10-3)]0-5 = 131.6 meters. 



