where W = 



P = 



C = 



E = 



I = 



uniform horizontal load 

 axial tensile load (lb) 

 length of pipe (ft) 

 Young's modulus (Ib/ft^ 

 moment of inertia (ft" ) 



lb/ft) 



Assuming the pipe is 10-3/4 inches in diameter and a horizontal 

 current velocity of 1/2 knot, it is possible to use the above equation to 

 compute the bending stress. The results are plotted in Figure B-7. 

































y/^^m 



ons 



^ 



■"^00 tons 



_^ 



50 tons 





^ ^ 















/ / 



/^ 



.^^ 











/ / 



^ 













/// 















/ // 





































un 



form 1/2-knot 



current 









































































3,000 6,000 9,000 12,000 



Stress (psi) 



Figure B-7. Pipe stress due to bending. 



118 



