5. (P/S)expected = (0.222) ( 1 .75) = 0.389 tcf 

 (p/S)ucL = (0.316) (1.75) = 0.553 tcf 

 (p/S)lcl = (0.130X1.75) = 0.228 tcf 

 Sexpected = 0.514 foot = 6.2 inches 

 Slcl = 0-360 foot = 4.32 inches 



SycL = 0.876 foot = 10.50 inches 



6. Check result with bearing capacity solution. Insert the following values 

 into Equation 12: 



K' = 0.02 tcf D = 1.5 feet 



p = 0.20 tsf 7^ = 0.01 tcf 



H' = 0.45 foot 



Solve resulting quadratic equation to find S 



S = 0.362 foot = 4.3 inches 



This is smaller than Syct calculated using the elastic solution. Therefore, the 

 elastic result is the more conservative value. The solution to the problem is; 



Sexpected = 6.2 inches 



expected range of S: 4.32 inches < S < 10.50 inches. 



FINDINGS 

 The Device 



1. A useful tool, capable of determining, in situ, the short-term bearing 

 pressure— settlement response of marine sediments loaded by a variety of 

 plates, was developed and successfully tested in cohesive sediments to a 

 water depth of 6,000 feet. 



2. All major components of the in-situ plate bearing device operated 

 satisfactorily. 



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