[47] 
Ge 
fp, (0,t) # © 
ae 
:) a f, (6,t) = gd, (3,7) 
b 
i) (7,0) =0 
In this set of equations u%*is the following function of the current change A/* which initiates 
the unsteady heat flow. 
2A 1* 
p*= [48] 
* 1 
[? (6) - Al 3] 
The solutions for the temperature increments as functions of the radius and time are given 
later by Equations [59] and [60]. The wire response is given by Equation [62]. 
As in the former problem, the solutions to the above set of equations were obtained by 
the use of Laplace transforms. 
The transformed problem becomes 
@ 
1a (, 9F1 w* J 0 (eT) ¥ 
r ar (- ts). PERO) 7,(ub) 
Od, eared 
ky @ 2) + P ¢,(a,8) = 0 
or 
. [49] 
C) 
“ob fa) Ge fy, $, (0,8) = 6, 0,8) 
f, (0,8) # 00 
where gee =, Pek 
7 y 
The solutions to this set of equations are 
——_ y* yr -Q P 1, (pr) 
ates = b — b 2 
Bs Oo) es eam ae co ao 20) 1, (pb) 
F Jo(ur) — Ig (Pr) [50] 
Jy (ub) 1, (p>) 
( es a Ge aD,, (qr yp (q7,9@) 
$, r,S) = 3 pe + A(s) q 01 qT, ko 00 q759 
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