1/2 

 CASE 1 - 4(mK) ' cos 9 < 1 



The integral limit in is between G and tt/Z, where 6 is given by 



-1 



4(niK) 



1/2 



-1 / 1 



4t 



(109) 



The integral path of u is given in Figure 4. 



\y 



"2 



1/2 



Figure 4 - Integral Path when 4(inK) cos 9 < 1 



1/2 

 CASE 2 - 4(niK) ' cos 6 > 1 



The poles in Equation (108) become 



1 - 2(mK)-^^^ cos 6 ± i[4(mK)''-^^ cos 6 -1] 

 2 m cos 9 



1/2 



(110) 



The integral limit in 9 is between and 



CASE 3 - cos 9 < 



With the change of the variable 9 = it - 

 becomes 



), the integral with respect to 



J ( } d6 . J 



Tr/2 o 



(K -m u cos 9) exp(ixu cos 9) 



.^1/2 1/2 ^ ■ 

 u - (K -m u cos 9) 



(111) 



The poles of Equation (111) are 



29 



