m = (sign m ) r sin 



cos = 



( 2^2. 



1/2 



( 2^ 2. 



1/2 



the numerator becomes 



1/2 1 2 2 ^/2 1/2 2 2 ^/2 1/2 



(m^+im^) ^ ~lj2 [ (™i"^2'^ "^"l"' +i(sign m2) [ (m^+m ) -m^] 



Finally, g„ can be express 



ed 



(1) 



'3 



2(2) 



1/2 



:/ 



2 2^/2 " 

 (m +m ) +m 



+i(sign m2) 



"22^/2 - 

 (m^+m ) -m^ 



1/2 



2 2 

 (m^+ra ) 



1/2 



dv 



(D.12) 



2 . n = 3 and x < 



Following the same method as that of Case 1, we can derive 



(1) _ K 

 '3 



2(2)^/2^ 



2 2^/2 - 

 (m^+m ) +m^ 



1/2 



+i(sign m2) 



- 2 2 1/2 



(m^+m ) -m^ 



1/2 



( 2^ 2. 

 (mj^+m2) 



1/2 



dv 



(D.13) 



where 



m2 = - 4(mK)"'"'2 v (K-mv^) 



(D.14) 



65 



