11 













































































t2 













T s 



WY = 8 - 9 " 



J 

















\0 . 



































8 , 































£ , 



n=>o 

































*0 



x 







vj. 









,^-- 



^5 



^ 



>^ 





















\ 



' 





^V 







Tj?'' 



^ 



^ 



-— * 





y = 3.0 





















T^S 





































"6"* 







\\ 





























T 

 WY " 



9.25 











\\ 





































\ 



\ 









































\ 

 i 



i 























Figure 6 - Illustration of Application of Figure 4 for an 

 Anchor Cable of 1-Inch Diameter and a Scope of 3.0 



Hence 



WY 



50,000 

 1800 



T B 

 T 



27.8 

 ~ 9.25 



= 27. 



= 3.01 



The holding power required, computed from Equation [8], is 



H = 



20,800 



1 — 0.0174 x 7 = 23 > 700 pounds 



The procedure for using the curves in Figure 2 is the same as that for the 

 curves in Figures 3, k, and 5 except that <j> = is given initially and the 

 value of S/Y is read by interpolation. 



These values and the results of similar calculations for other 

 lengths and diameters for this example are summarized in Table 2. 



It will be assumed that it is impracticable to use more than 360O 

 feet of cable, or an S/Y greater than 2.0. For an S/Y of 2, Table 2 shows 

 that the factor of safety increases almost linearly with diameter of cable. 

 The holding power, however, reaches a minimum of about 30,700 pounds with a 

 cable of 2-inch diameter. If a safety factor of 3-1 is assumed to be ade- 

 quate, interpolation from Table 2 indicates that the ship could be anchored 

 with 3600 feet of 17/1 6-inch wire rope with an anchor having a holding power 



