The solution of (62) is 



W^ Jz) 



.r„.2 



1 — cos 



gr. 



2l 



T 1/2 



2 /■2 

 'Mo -' 



COS 



g^o 



(f)Mir 





1/2 

 77H-I 



i v-^^ J 





g^o 



(^f^(if 





1/2 

 77H 







.,2 /■2 







(!) ^C 



^ (63) 



The amplitude factor 



'i, m 



gr^rr^ 



(f)^(i 



with 



k^_^ = 10^28 pj^-1 ggj,-3^ gp^ ^ 10"*sec-2, £= m = 1 



L = B = 10,000 km 



has the magnitude 10 ~^ cm sec "^ from which an amplitude of 10"^ 

 results for 4 . Therefore the amplitudes of the first and second terms in the 

 brackets are negligible. The third contains a resonance factor. 



For any combination of wavelength which fulfills the condition 



(f)*(i) 



2 (2«-l)2 r^^2 _ ^2^ 



S^O^' 



■ , n = ±l, ±2,...., 



(64) 



it follows that M^jg m~*~ °° • Introducing friction, we get finite amplitudes. 



It can be shown that the amplitudes ^ are of the magnitude 10 meters. Two 

 cases are distinguished: 



(1) The case where angular frequency of internal waves is greater than 

 Coriolis parameter, i.e., cj^^yf^ 



24 



