]^ 



\ -W'S ^^ * S'\^~T 



uh, (l+h,4-^ ) + -4— L 



1 h ^ 3,. 2 ■ 2 



Jp^h^^ (14.-1) .^A^^^^ (1+-^) + p^xlx^ 



PlfP, 

 2 " 



-kx2x|. Yp_^^ 2x§ 



(p,h, ) (2+4) +(. 



Po- 



2 ''I 



^ra 



-^> 



] 



where p = pi 

 ' c - U 



/\:^3 



) - 369 pounds per square foot 



X 1 X- 



) \ (2*^ 



(99) 



j^ - r^62o ^ 7720 + 3600 + 209J -T331 + 1865T 



= 13 J 953 foot pounds per foot of wall 



33>. For stabilityj, the sum of all moments about C must be zero. Then 

 if H is the point of deepest pile penetration. 



2h, 



(GG 



=) (h, 



hgxR 



(100) 



where h^ x 

 o 



= p. 



Therefore (h^) (CiS 



hj - 2^ 



(101) 



or in this case 



(hg)^ (9.36 + |hg) = i^-igpLl^ 131 



from T^iiich h^ "^ 3„U feet. 



336. Since point G is itself 2,36 feet below the dredged bottom, the 

 pile raust penetrate a distance 3oU + 2»ii = 5o8 feet below the dredged bottom, 

 at which point the pressure p^ would be 



p_ s R X h^ = 21Ii. X 3.U = 728 pounds per souare foot. 



The minimum length of pile for stability -with the deadinan tie-rod one foot 

 above the low water line would be 18,8 f eet „ 



(102) 



337 « i^l^^^A"!^. J^-Q^A^^g Momant for MinJ-miLii L en gth Pile. - The maximum bending 

 moment in the wall would occur at that point above the dredged bottom '/iiere the 

 shear passes through zero. The shear Stj, at the dredged bottom. F is given by 

 the sum of the forces below that point, which sum is the algebraic sun of the 



163 



