wall (T) times the length of waJ-l supported by each deadmanj divided by the 

 deadman xd-dth. In the case of a continuous deadman this earth force must 

 equal T, Assuming a continu.ous deadman, 



T -(li^~ii) xd^ (133) 



where p^ = R, x d^,, 



and p- a p-^ -> R, x d, = R^ (d,^ * d, ") 



^L K d d d K d- 



Therefore 



T- ^d ^^^K * ^d) , 



T = - ■ ■ g — - X d^ 



if we call T T >.miji^j 



■^ ~ •sio'T ~ T' and solve for d^^ 



2 



O'vi - d 

 d 



(13ii) 



3611. , In additions the sum of the moments of these forces about (say) 

 K must equal aero, 



2 



T (d^ - dj^) ^ J^ -. R^d^ X -|- X -^i- (135) 



„ a K d i d d 



2 3 



which, when the value of d^.- and T' above ar-e substituted^ gives 



dj^ - 12 d T' d + 12 (T')~ = (136) 



an eqtfe.tion in d, which must be solved by trial and error 



36^7. This quartic: equation may have as many 

 but nc' more. One of these roots 1-10.11 be slightly 



36^, This quartic: equation may have as many as two positive ^ oots 

 e roots 1-7111 be slightly small than d, ^ •;;12d™T' 



176 



