1.2 m.j relation, 2L ■ 4; relation L = 15; then,. serair.height , h = 1.2 

 H h 2x15 



= 0.04- m. 



By application of our formula, we obtain the limiting 

 slope : 



i 



■ 4. .f oToZ - 0.568 

 0.45 V 9.81 



that is, the batter: 



t = 1 = 1.76 

 h 0.568 . 



(b) Data. 



T - 0.45 sec; H = 0.3 m. ; 2L = 1.2 m.j 2L =» 4 J h - 20j 



H h 



h ■■ 1 » 2 ■ °»°3 a. , 

 2x20 



we obtain: 



i * 4 /0.03 - 0.492 



0.45 V 9.J 



. -81 



that is, the batter: 



t * 1 = 2.03 



H 0.492 



craves Classified Long 



(c) Data. 



T * 0.8 sec; H = 0.25 m.j 2L = 2.3 m.; 2L - 9.3} L m 15; 



H h 



h ■ 2.3 =» 0.077 m. 



2 x 15 



we obtain: 







i ■ 4 . 

 0.8 



,/ 0.077 

 V 9.81 



= 0.442 



that is, the batter; 







t = 1 



= 2,26 





H 0.442 





