_FIND: 



(a) The fill factor, R^ 



(b) The renourishment factor, Rj 

 SOLUTION ; 



(a) Using equation (5-2) 



M *84 ^ '''16 

 "<t. 2 



and 



M = 3-10 + 1>86 ^ 2.48 (0.18 mm) 

 (pn z 



M 3.25 + 0.17 , ,, .- -, . 

 M , = 2 = l«'l (0.31 nun) 



Using equation (5-1) 



_ '''84 ~ 'I'le 



'(j)n 1 



and 



°<|) = T 



o,„ = 3.10 - 1.86 = 0,62 



J - 3.25 - 0.17 _ 1 .. 



The phi sorting ratio is 



^ = Hf — 



and the phi mean difference is 



^6b ^4>n _ 1.71 - 2.48 _ , o. 



From Figure 5-3, the fill factor is 



R^ = 1.15 



(b) From Figure 5-4 and equation (5-3) , the renourishment factor is 



5-18 



