From Equation 7-6, 



0.217 /h-d 

 / ,i\i/ - tanh-l : 



Q = [(32.2) (0.035) (5)3]'''^ 



0.217 



0.08 



tanh 



h-d 



The value of 



h-d. 



15-10 



IS = 0.294 . 



17.0 



To evaluate tanh"-^ [(h-dg)/R] find 0.294 in column 4 of either Table 

 C-1 or C-2, Appendix C, and read the value of tanh"-^ [(h-d3)/R] from 

 column 3. Therefore, 



tanh"' (0.294) « 0.31 . 



Calculating the exponent, 



0.217(0.31) 



0.08 



therefore. 



= 0.84 ; 



Q = 11.9 e-°-«^ = 11.9 (0.431) = 5.1 ftV(sec-ft) . 



For an onshore wind velocity of 35 mph, the value of W~ is found by 

 interpolation. 



30 mph; Wy = 0.5 , 



35 mph; Wr = 0.75, 



60 mph; Wr = 2.0. 



From Equation 7-8, 



where 



k' = 1 + W. 



Wy = 0.75, 



h-d 



+ 0.1 sin 



h-d. 



- 0.3, 



.a„- , -1== 22» . 



and 



sin 22 = 0.37 



7-51 



