From Equation 7-34, compute 



Cm^ (2.0) (1) 



W = = -^^ -^-^ = 0.29. 



C^H (0.7) (10) 



Interpolation between Figures 7-49 and 7-50 for (fi^ is required. 

 Calculate 



H 10 



— r = r = 0.0031, 



gT2 (32.2) (10)2 



and recall that 



d 

 — : = 0.00466 



Find the point on Figures 7-49 and 7-50 corresponding to the computed 

 values of H/gT^ and d/gT^ and determine (() 



m 



Figure 7-49 W = 0.1 ; <t>^ = 0.35, 



Interpolated Value W = 0.29 ; 0^ =* 0.365, 

 Figure 7-50 W = 0.5 ; 0^ = 0.38. 



From Equation 7-35, the maximum force is 



Fm = K wC^H^D. 



F^ = 0.365 (64) (0.7) (10)2 (1) ^ i,635lbs. 

 say 



F_ = 1,600 lbs. 



To calculate the inertia moment component, enter Figure 7-45 with 



-— = 0.00466. 



and H = 0.87 H^ interpolate between H = H^ and H = 3/4 H^ to find, 



S,m = 0.81. 

 Similarly from Figure 7-46 for the drag moment component, determine 



Sr.™ = 1.02. 



"Dm 



7-91 



