FIND : The maximum total horizontal force and the moment around the 

 mudline of the pile. 



SOLUTION : The procedure used is identical to that of the preceding 

 problem. Calculate, 



d 100 



— ; = r = 0.031, 



gT2 (32.2) (10)2 



and enter Figure 7-47 to the breaking-limit curve and read 



— : = 0.0205. 



Therefore 



Hj, = 0.0205 gT^ = 0.0205 (32.2) (10)^ = 66 ft., 

 and 



H 10 



= — = 0.15 . 



Hj, 66 



From Figures 7-43 and 7-44, using d/gT^ = 0.031 and interpolating 

 between H « and H = 1/4 H^,, for H = 0.15 H^,, 



^Dm = 0-20 

 From Equation 7-30, 



F.m = C^Pg — HK.^. 



7r(_l)2 

 4 

 and from Equation 7-31, 



1 

 2 



F,.^ = 2.0(2)(32.2j ^7^ (10) (0.44) = 445 lbs. 



Fom = Cd - pgDH^ K^^ , 



^Dm = 1-2 (0.5) (2) (32.2) (1) (10)2 (0.20) ^ 773 lbs. 

 Compute W from Equation 7-34, 



^M^ 2.0(1.0) 



W = = ^ = 0.16 . 



C^H 1.2(10) 



7-93 



