From Figure 7-40, for d/gT^ = 0.0183, 



— = 0.75 , 



and 



gT^ (32.2) (12)2 



L. = 0.75 L = 0.75 = 0.75 = 554 ft. 



^ " 27r 27r 



From Figure 7-41, for d/gT^ = 0.0183, 



H = '■'' ' 

 and therefore, 



T?^ = 0.68 H = 0.68 (35) = 23.8 ft., 

 say 



T?^ = 24 ft. 



The structure supported by the pile must be 24 feet above the still- 

 water line to avoid uplift forces on the superstructure by the given 

 wave. 



Calculate, from Equation 7-14, 

 D 4 



L^ 554 



0.0072 < 0.05 



Therefore Equation 7-13 is valid. 

 From Figure 7-47, 



= 0.54 



^Dm 



= 0.82 



7-1 



