Interpolation between Figures 7-77 and 7-78 for 6 , using — ;r = 0.031 

 and -2- = 0.0031 , gives ^^ 



(() = 0.11 



From equation (7-42), the maximum total force Is 



F = d) w C„ H^D 

 m m D 



F = 0.11 (10,047) (1.2) (3)^ (0.3) = 3,581 N (805 lb) 



m 



say 



F = 3600 N (809 lb) 



m 



From Figures 7-73 and 7-74, for H = 0.15 H, , 



and 



S,-^ = 0.57 



hm = 0-69 



From equation (7-39), 



M. = F. dS. = 1,875 (30.0) (0.57) = 32.1 kN-m (23,700 ft-lb) 



and from equation (7-40), 



>L = F^ d S^ = 3,255 (30.0) (0.69) = 67.4 kN-m (49,700 ft-lb) 



Dm Dm Dm 



Interpolation between Figures 7-81 and 7-82 with W = 6.16 gives 



a = 0.08 



m 



The maximum total moment about the mud line from equation (7-43) is, 



M = a w C„H Dd 



m m D 



M = 0.08 (10,047) (1.2) (3)^ (0.3) (30.0) = 78.1 kN-m (57,600 ft-lb) 



If calculations show the pile diameter to be too small, noting that F. is 

 proportional to D and F^ is proportional to D will allow adjustment 

 of the force for a change in pile diameter. For example, for the same wave 

 conditions and a 0.6-m (2-ft) -diameter pile the forces become 



7-131 



