SOLUTION ; From Example Problem 31, 



y = 5.50 m (18.1 ft) 



(T = 6 s) 

 u^ = 2.50 m (8.2 ft) 



Compute b/y for each case 



— = 44 = 0.818 



y 5.5 



— = 44 = 1-80 > 1.0 

 y, 2.5 



(T = 6 s) 



Entering Figure 7-97 with the computed value of b/y , determine the values 

 of rj? and r_ from the appropriate curve. For the wave with T = 6 s , 



therefore. 



and 



therefore. 



Reduced forces and moments may be calculated from equations (7-78) and 

 (7-80) using the values of F and M found in the example problem of the 

 previous section; for T = 6 s . 



F' = 0.968 (101.7) = 98.5 kN/m (6,750 lb/ft) 



M^ = 0.912 (163.8) = 149.4 kN-m (33,590 ^W^ ) 



f; = 1.0 (17.1) = 17.1 kN/m (1,200 lb/ft) 

 K = 1.0 (11.8) = 11.8 kN-m/m (2,650 ^^j^ ) 



7-176 



