Equation (7-85) can now be used to find p^^j . 



p^ = 101 (10) ^ l^ (3.9 + 2.5) 



= 331 kN/m2 (6,913 Ib/ft^) (T = 6 s) 



A similar analysis for the 10-second wave gives. 



p^ = 182 kN/m^ (3,801 Ib/ft^) (T = 10 s) 



The above values can be obtained more rapidly by using Figure 7-100, a 

 graphical representation of the above procedure. To use the figure, 

 calculate for the 6-second wave, 



d 

 e 2.5 



= = 0.0071 



2 2 



gT 9.81 (6) 



Enter Figure 7-100 with the calculated value of dg/gT , using the curve 

 for m = 0.05 , and read the value of p^^/wHj, . 



wH^ 



= 12.0 



Using the calculated values of Hj, , 



p^ = 12.0wH^ = 12.0 (10) (2.8) = 336 kN/m^ (7,017 Ib/ft^) 



For the 10-second wave, 



p^ = 5.5wH2, = 5.5 (10) (3.2) = 176 kN/m^ (3,676 Ib/ft^) (T = 10 s) 

 The force can be evaluated from equation (7-86) thusly: 



Pffi u 331 (2 8) 

 \ = — ^ = J-- — = 309 kN/m (21,164 lb/ft) (T = 6 s) 



and 



%, = 194 kN/m (13,287 lb/ft) (T = 10 s) 



7-184 



