The overturning moments are given by equation (7-87) as 



M = R d =309 (2.5) = 772 ^^^ (173,561 ^^^ ) (T = 6 s) 



m m s m rt 



and 



M = 485 ^^ (109,038 ^|^ ) (T = 10 s) 



mm rt 



For the example, the' total forces, including the hydrostatic force from 

 equations (7-89) and (7-90), 



R = 309 + ^^ 7^ =-^— = 309 + 76 = 385 kN/m (26,382 lb/ft) 



* ^ (T = 6 s) 



R^ = 278 kN/m (19,041 lb/ft) (T = 10 s) 



Then 



M^ = M + M 

 t m s 



1012.5 + ^ 



M = 111 + ^^-7 ^-^ ■ 111 + 99 



t 6 



M = 871 i^^ (195,818 %i^ ) (T = 6 s) 



t m ' ft 



and 



M = 600 -^^^ (134,892 ^^^ ) (T = 10 s) 



^ m rt 



(b) If the nearshore slope is 1:100 (m = 0.01), the maximum breaker heights 

 must be recomputed using the procedure given in Section I,2,b. For a 6- 

 second wave on a 0.01 slope the results of an analysis similar to the 

 preceding gives 



H = 2.1 m fd, = 2.6 m (7.9 ft) > d ] 

 b b e 



p = 337 kN/m^ (7,035 Ib/ft^) (T = 6 s) 



m 



7-186 



