R = 309 kN/m (21,164 lb/ft) 

 m 



M = 772 MiE (173,561 ft^ ) 



(T = 6 s) 



and 



H = 3.2 m (10.5 ft) [d, = 3.0 m > d 1 

 b b s 



R = 194 kN/m (13,287 lb/ft) 

 m 



M = 485 kN-m/m (109,038 ft-lb/ft) 

 m 



(T = 10 s) 



For the breaker with a period of 6 seconds, the height of the breaker crest 

 above the bottom is 



.4 



2.5 + 



2.8 



= 3.9 m (12.8 ft) 



The value of b' as defined in Figure 7-102 is 1.9 m (6.2 ft) (i.e., the 

 breaker height H, minus the height obtained by subtracting the wall crest 

 elevation from the breaker crest elevation). Calculate 



1.9 



\ 2.8 

 From Figure 7-102, 



= 0.679 



(T = 6 s) 



r = 0.83 



m 



therefore, from equation (7-91), 



R' = r R = 0.83 (309) = 256 kN/m (17,540 lb/ft) 



m mm 



(T = 6 s) 



From Figure 7-103, entering with b/H" = 0.679 , 



b 



|i=0.57 

 b 



hence 



^ _ 0.57(2.8) _ n sn n, 

 a = 7i = O.oO m 



and from equation (7-93) 



M' = R 



m m 



r (d + al - a1 

 m s J 



= 309 [0.83 (2.5 + 0.80) -0.80] 



7-191 



