L^ = 1.5606 (7.78)^ = 94.470 m 



L^ = 94.47 "-^^^^ 



f = 0.1773 — L = 76.14 m (see 'feble C-1) 



Ij 



cosh — — = 1.687 



Li 



1 + 0.9 (10.05) (6) ,- „„ , „/ 2 



Pi = — 2 r:687 — = ^^-^^^ ^^/"^ 



p = w d (hydrostatic pressure) 

 p = (10.05) (13.5) = 135.68 kN/m^ 



Equations for uplift forces/unit length: 



p Lg (33.957) (l J 

 h=—2 2 = ''-''' "^c 



\ = P2 L^ = 135.68 L^ 



(2) Summation of Vertical Forces . 



B^ + B2 - W + Ry^ = 



16.979 L^ + 135.68 L^ - 275.26 L^ + Ry = 

 Ry= 122.601 Lg kN/m 



(3) Summation of Moments About A . 



^l(f)^ + ^2 (IK " KiX ■" ^(i)^<^ ^\et=^ 



16.979 (j) Lj? + 135.68 (j) lJ - 275.26 (|j L^^ + 122.601 (-j) 



2 ^ 5894.2 

 c 17.604 



L, = 18.298 m 



This is the width required to prevent negative soil bearing pressure under 



caisson (reaction within middle third). Assume L = 18.5 m . 



a 



\} + 5894.2 = 



^ = vertical component of reaction R 



8-80 



