and Equation 2-23 reduces to 



H 

 B = - 



2 



Thus, 



10 1 



A = = 7.78 feet , 



2 (0.6430) 



H 10 



B = - = — = 5.0 feet 

 2 2 



When z = - d, 



A = = = 5 96 feet 



2sinh(27rd/L) 2(0.8394) 



and, B = 0. 



(b) With Uo = 10-45 feet, and z = - 25, evaluate the exponent of e 

 for use in Equation 2-24, noting that L = L^, 



/27rz\ 27r(- 25) 



= — ^ = - 0.307 , 



\L I 512 



thus 



e-0.307 = 0.736 . 



Therefore, 



H 27:2/ 10.45 



A=B= — e ^^ = (0.736) = 3.85 feet . 



2 2 



The maximum displacement or diameter of the orbit circle would 

 be 2(3.85) = 7.70 feet. 



r ^ ^o "512 



Cc) z = = = - 256 feet , 



2 2 



27rz 2-n(- 256) 



-— = = - 3.142 . 



L 512 



Using Table C-4 of Appendix C, 



g-3.142 ^ 0.043. 



H^ 2mL 10.45 



~ e f^ = -^^— (0.043) = 0.225 feet . 



2-21 



A = B 



2 2 



