FIND: Wind setup at the new time level. 



SOLUTION : The wind stress coefficiei t given by Equation 3-59 is 



k = K, + K, (l - ^) = 1-1 X 1«" + 2.5 X 10- (l-^^j 

 = 2.27 X 10"* 



From Equation 3-91 



4KAt|Q;'^^ I 



G = 1 + 



(D?.:^ + D?+3/J"{b,.^j,+b,>3/J 



4 (0.003) (0.2) I 0.0707 I = i oi 



*^ ~ "^ "^ [(0.0162)2 + (0.0132)2] (26.3 + 21.0) 



The two terms needed in the evaluation of Q, (Equation 3-89) are 



given by 



f (b.>'^+b,,3/^) (kW^ COS 0):';/ 



0-2 



(26.3 + 21.0) (2.27 XIO'^) (50.5)^ (1) = 0.0274 



and 



gAt 



{^i+'A '^ ^i+3/2) {^i+'A ^1 + 3/2)" 



= - 0.0463 



2Ax 



79,000 (0.2) (0.426 + 0.278) (3.32-3.76) 

 (2) (10) (5,280) 



The volume flow rate from Equation 3-89 is 



QLV = ~ [0.070 + 0.0274-0.0463] = 0.0513 mi? /hr. 



^^ 1.0129 



3-139 



