-where S(z-') = tt a- (z') = cross-sectional area of i spar at z'. 



The combination of these formulas and definitions -with the previous 

 pressure results yields for the force and moment components 



Xj^ = 2pgkAcos(kaQCOs6^-cot)TQ- p(xQ--YaQ sin9.)SQ- ppS, [14a] 



Y^ = - p(yO + \ aQ cos e.)SQ + pa Sj [14b] 



Z- - pgkA sin(kaQ cos 6. -wt)TQ + pgSj, 



[14c] 



-pg[A sin(kaQ cosS- -cot) + Zq + o slq sin 9. - ^ a.Q cosB.] S(0) 



A. = pgkaQ sin 6- A sin(kaQ cos 9- - cot) Tq f 14d] 



+ Pg(yO + ^0 si^ ^i + \ ^0 cos 9.)Sq + p(yQ + Y ag cos 9. - go) S^ - p a S2 



- pg^Q sin 9. [zq + Q'aQsin9. - |3aQCOs9. + AsinfkaQ cos9. -cot)]S(0) 



B^ = - pgkaQ cos9.Asin(kaQ cos9^ - cot)TQ + 2 pgkAcos(kaQ cos9-- cot)Tj 



- pg(xQ + aQ cos 9. - Y aQ sin9.)SQ - p (xq - y ag sin 9. + g p) S^^ - p (3 S2 



+ pgaQCOs9^ [zq + Q'aQsin9^ - Pag cos9- + Asin(kaQ cos9. - wt)] S(0) 



[14e] 



r. = - 2 pgkaQ sin 9- A cos(kaQ cos 9- - cot)TQ 



[14f] 



2 



+ p [aQ sin 9. Xq - a.Q cos 9- yQ - a^y] Sq 



+ p [ aQ sin 9- (3 + aQ cos 9- a] S, 



S(9) is the cross-sectional area at z- = 9 when the whole system is at 

 rest and in equilibrium. 



12 



