933 
4 -1 
5/32 Fa 1.22 x 10° sec (I-66) 
4 -1 
5/8 oe = 1.82 x 10° sec (I-67) 
If ¥(0) = response (relative to step response) to an arbitrary 
shock wave having time parameter 0, 
A = piston area 
mo deformation of ball (in-) 
P = peak pressure (1b/in?) 
Ey 
ot I-68 
2a ¥(0) ( 
4 
P5/32 ane = 3.19 x 10 Ye) (I-69) 
ea ee 
Pp = 7-62 x 10 I-70 
15. Gauge Constants®) 
Constants for 5/32 in- Balls (Under water) 
M = mass of piston + ; mass of ball + spr 
13-9 + 00097 + 0-68 = 14-7 g = 1-01 x 107° slugs 
Piston area = 0.197 in? = 1-37 x 107° rt” 
Be. Constants for 3/8 in. Balls 
M = 13-9 + 1e3 + 0668 = 15088 g = 1.09 x 10m2 slugs 
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