3 ( 

 2 

 ~ 1 



2 -I 



o 



) 



0.1 0.2 



Time (fraction of tidal cycle), t/T 

 0.3 0.4 0.5 0.6 0.7 0.8 0.9 



1.0 



- 



1 1 



MTL 



1 1 l I I l l 

 s>r ^ — Tidal Curve 



l 



- 





\ ph 



-d s 



o _ 2 



— -3 



c 



o 



~ -4 



o 



> 



J2 -5 



LlI 



-6 

 -7 



" 



h=6.0ft 



Weir-Crest Elevation = -1.5 



d s (t) 



— Bottom Elevation =-7.5 



^ — " 





Figure 19. Water level at weir as a function of time ( 



Table 5. 



Computation of 

 overtopping for 



wave transmission by 

 example problem 3. 



Row 



Time 

 (fraction of 



Depth 



H i 



H t / Hi 



H t 





tidal period) 



(ft) 



(ft) 





(ft) 



1 







5.00 



3.90 1 



0.347 



1.35 



2 



0.05 



5.10 



3.98 1 



0.360 



1.43 



3 



0.10 



5.50 



4.26 1 



0.406 



1.73 



4 



0.15 



6.00 



4.68 1 



0.456 



2.14 



5 



0.20 



6.70 



5.23 1 



0.514 



2.69 



6 



0.25 



7.50 



5.85 1 



0.568 



3.32 



7 



0.30 



8.20 



6.00 



0.615 



3.69 



8 



0.35 



8.95 



6.00 



0.667 



4.00 



9 



0.40 



9.50 



6.00 



0.704 



4.23 



10 



0.45 



9.85 



6.00 



0.727 



4.36 



11 



0.50 



10.00 



6.00 



0.737 



4.42 



12 2 



0.55 



9.85 



6.00 



0.727 



4.36 



1 Waves are depth-limited and break, seaward of 

 weir; incident wave heights are given approxi- 

 mately by E ± = 0.78 d. 



2 Because of tidal curve symmetry, solution is 

 symmetric about t = 0.50. 



38 



