Table 6. Computation of wave transmiss 

 overtopping for example probl 



ion by 

 em 4. 



Row 



Time 

 (fraction of 



Depth 



»i 



K 



R 



V H i 



H t 





tidal period) 



(ft) 



(ft) 





(ft) 





(ft) 



1 







5.00 



3.90 1 



4.58 



3.74 



0.096 



0.37 



2 



0.05 



5.10 



3.98 1 



4.54 



3.80 



0.107 



0.43 



3 



0.10 



5.50 



4.26 1 



4.39 



4.02 



0.146 



0.62 



4 



0.15 



6.00 



4.68 1 



4.28 



4.36 



0.190 



0.89 



5 



0.20 



6.70 



5.23 1 



3.96 



4.78 



0.241 



1.26 



6 



0.25 



7.50 



5.85 1 



3.74 



5.24 



0.290 



1.70 



7 



0.30 



8.20 



6.00 



3.70 



5.36 



0.328 



1.97 



8 



0.35 



8.95 



6.00 



3.70 



5.36 



0.368 



2.21 



9 



0.40 



9.50 



6.00 



3.70 



5.36 



0.398 



2.39 



10 



0.45 



9.85 



6.00 



3.70 



5.36 



0.417 



2.50 



11 



0.50 



10.00 



6.00 



3.70 



5.36 



0.425 



2.55 



12 



0.55 



9.85 



6.00 



3.70 



5.36 



0.417 



2.50 



1 Waves are depth-limited and break seaward of weir; 

 incident wave heights are given approximately by 

 H = 0.78 d. 



2 Because of tidal curve symmetry, solution is symmetric 

 about t = 0.50. 



5 - 



I - 



r— ' 



-a- 



1 



1 1 



1 



1 



1 

 Incident 



1 

 Wave H 



1 1 

 eight 



■^^ 



f s 



.^■fl -A A ft ft — -ft — 



Wove Runup 



-ft- -A--. 



- 







Transmitted 



Wove 



Height 













- 



- 





1 



1 1 





i 



I 



i 



1 





1 



- 



0.2 



0.3 0.4 0.5 0.6 0.7 0.8 

 Time (fraction of tidal cycle), t/T 



0.9 



1.0 



Figure 21. Time variation of incident and transmitted 

 wave heights. 



40 



