and 



n , n=l,2, . . . 



^n (p+n)(p+n+3/2)(P-l) ^n-1 ' ^o ■*■ 



1 , n=0 



C = C { (D-3d) 



n o _ 



a , n=l , 2 , . . . 



^n (q-n) (q-n+1/4) (Q-1) ^n-1 ' ^o"-*- 



With the definitions, 



S=EA , S = E6 , Sq=E6 



n=0 " P n=0 " n=0 



q = - i - /(l/64) + (l/Q)" 



(D-4) 



(D-5) 



S' = E (n+l)A , S' = Z (p+n)B , S' = E (q-n)6 

 n=0 '^ n=0 ^ n=0 



from continuity at the breaker line, 



B = (SS' - S'S )/(S'S - S S') 

 o q q p q p q 



C = (SS' - S'S )/(S'S - S S') 

 o p p p q p q 



where in the above 



IT r tan B ^ IT r _ fT^ £.\ 



T = ^ Q = -X- TT- tan B (D-6) 



^ ^f 1+3y2/8 ^ ^f 



and 



P = - I + /(9/16)+(l/P) 



243 



