Re-writing; 



^ - ^c^ = V^ (5.4a) 



Pc - ^2 = 22/^2 



And, from continuity; 



Adding Equations 5.4a and 5.4b; 



(5.4b) 



2l = 22 ^ 2 (5.5) 



^-^2 = \-%-^2(^ + i^) (5.6) 



The transducer diaphragm displaces a volume V-^ proportional to the 

 change in pressure across the transducer chamber: 



AV = aAP = a(P - P ) /c -,^ 



c c ^1 ^2 (5-7) 



Re-writing Equation 5.7 and expressing the change in volume in terms 

 of the fluid f-low Q; 



AP = P - P = — AV = - / Q dt' f5 R") 



c c c a c a •' k-j-oj 



