The vertical component of surface area is equal to the area of a 

 cylinder having a radius equal to the average radius of the frustrum 

 or in this case .5 ft. 



A^ = ^ (.5) (.5) 



= .7854 ft^ 



The horizontal component of area is equal to the horizontal 

 projection of the curved surface of the frustrum. 



..75.2 /.25.2 

 A^ = . (— ) - . (— ) 



= .44178 - .04908 



= .39370 ft^ 



A = A + lOA, 

 e V n 



= 4.7123 



£ (ft) 



\ ("') 



K (ft') 



A^ (ft) 2 







.0491 



.0982 



.5892 



0.5 



.3927 



.7854 



4.7124 



1.0 



.7854 



1.5708 



9.4248 



1.5 



1.1781 



2.3562 



14.1372 



2.0 



1.5708 



3.1416 



18.8496 



2.5 



1.9635 



3.9271 



23.5620 



10.0 



3.8779 



15.6027 



54.3887 



10.5 







15.7079 



15.7079 



11.0 







15.7079 



15.7079 



2. A is calculated and tabulated above. 



e 



3. The strength profile is given in Figure 20. 



4. V = 20 ft/sec 

 o 



23 



