138 Transactions.— Miscellaneous. 
INCHES. 
37 = log 156820 
88330 =  colog 5:05389 
[uU 
eonstant log 441570 
Correction  10-^9 = log. 1.:03779 
INCHES. 
21 = log . 1:32222 
88330 = -Golog 5105389 
con ni Pe 4:41570 
Correcttion 6*2 = log 079181 
; Corrected Angles. 
Elev. 1° 14' 13” + 10.9 — 1? 14' 28-9 
Dep. 1° 27 50 — 6 2 = 1 22 4*8 
8 199 = 4999 
3 
Distance from Bryant’s Hill to tog s Hill — 88632 links 
ithe rue distance as found by Triangula = 97 
Difference 565 a 
Which is about half a chain per mile. 
Having found the contained arc, or distance between the stations, in 
links, by the rules given above, the difference in altitude may be obtained in 
the usual way, viz., by converting the links into feet and then multiplying 
the distance in feet between the stations by the tangent of the true angle 
of elevation or depression. (Norr.—The true angle of elevation or 
depression is half the sum of the observed reciprocal angles, when one 
is an elevation; or half the difference when both are depressions; or, 
generally, if zenith distances are used, the true vertical angle is equal to 
half the difference of the reciprocal zenith distances;—of course sup- 
posing the eye and object corrections to have been applied.) 
But instead of finding the distance between the stations in links, and 
then converting it into feet, it would be more simple to find the distance in 
feet at once, by MA the factor 117 instead of 177-3, as before explained :— 
Example. 
Bryant’s Hill to enke s E Corrected Elev. 1° 14’ 23⁄9 
Barker’s Hill to Bryant’s " Dep. 1° 22’ 437-8 
Diff. 819^9 — 4999 
Sum. 2° 87077 
$ Sum. 1° 18’ 338 
499.9 = log 2-698883 
117 = constant log 2-068186 
1*1999^8 = tangent  8:359040 
1337°0 feet = 8126109 
