OM HAFSVATTNET UTMED BOHUSLÄNSKA KUSTEN. 



37 



b) Hafsvatten af sp. vigten 1.01982 vid jf|. 



Villkorseqvationer. 



1 . a + 1.6 + 1 . c = O.000034. 



5.a + 25.6+ 125 . c = 0.000296. 



10 . a + 100 . 6 + 1000 . c = 0.000879. 



15. a + 225. 6 + 3375. c = 0.001719. 



16. a + 256. b + 4096 

 18. a + 324. b + 5832 



20 . a + 400 . b + 8000 

 Dessa leda till slutsystemet 



C = 0.001926. 

 C = 0.002357. 

 C— 0.002818. 



1331 . a + 22429 . b + 391763 . c = 



22429 . a + 391763 . b + 7000645 . c = 



391763'. a + 7000645 . b + 127195691 . c = 



0.165691. 



2.866033. 



50.896579. 



hvaraf 



a — 0.000029472623 

 b — 0.000000071422 

 C = — 0.00000002479301 



y = 1 + 0.0000294726 . t. 

 + 0.0000060714 . t 2 . 

 — 0.000000024793 . t 3 



Log. a — 5.4694188. 

 Log. b = 6.7832904. 

 Log. C = 8.394329372. 



(A. 2). 



c) Hafsvatten af sp. vigten 1.02306 vid yf-1. 



Villkorseqvationer : 



5 . a + 25.6+ 125 . c — O.000350. 

 10 . a + 100 . b + 1000 . c = 0.000988. 



15 . a + 225 . 6 + 3375 . c = 0.001873. 



16 . a + 256 . 6 + 4096 . c = O.002078. 



17 . a + 289 . 6 + 4913 . c = O.002297. 



18 . a + 324 . 6 + 5832 . c == O.002521. 

 20 . a + 400 . b + 8000 . c = 0.00299?. 



Dessa leda till slutsystemet : 



1619. a + 27341.6+ 475283. c = 0.217265. 



27341 . a + 475283 . 6 + 8420501 . c = 3.738505. 



475283 . a + 8420501 . 6 + 151333259 . c = 65.778871. 



hvaraf 



a= 0.000036182271 

 6 = 0.000006821816 

 C = — 0.00000005855327 



Log. a = 5.5584959. 

 Log. 6 = 6.8339000. 

 Log. C = 8.7675512«. 



