629 
If we cut this beam at B the whole extra charge 
acts on the spring under C, so that in the determination of the 
points A >, B , C only the point C appears to have an extra 
00 00 00 00 
descent. 
Without any diffienlty with the help of the link-polygons 
Palin Retain CnandeALtoillaone 2 oro Nn Cathe points C and C 
00 00 00 10 10 00 10 
ean then be constructed, which together with the point C and C 
00 10 
determine the point C through which the beam ABC must pass at 
„0 
its extremity C, when besides the given charges it must bear in C 
a force of 4 ton. 
On the supposition M‚/==0 the side 12” u is Vo eN Q can 
now be prolonged as far as lvirr. After that from Ca segment C, C'=c 
.0 0 .0 
must be drawn in downward direction in order to make it possible 
to draw the side C' oVIII oD. In this way, however, the point oD 
„0 
is determined. 
10. It is far more difficult to find the point C, through 
oi 
which the beam ASC, considered as a whole, must pass if in C a 
moment of transition of one metreton is applied. For, when the 
connection of the beam above B is broken, this moment will, in 
opposition to the force just applied in C, besides on C also exert 
its influence on the point B. 
The place of the point B is taken by a point B, which lies 7 
00 01 
p : 7 (10 é u Y 
higher. In the same way the point C' lies a distance 15 below C, 
o1 00 
because the couple of unity acting on the field BC as well as that, 
. : u : 
acting on the field CD, gives an extra descent — to the spring under C. 
4 
In case the moment of transition in B is supposed to be zero 
we have therefore to do with the link-polygon A'oj, [Io1, B, 
01 
oVs, oVI, C, of which the two last sides now deviate and cut a segment 
01 
of known length from /r. 
') By a second index, placed to the right or to the left of a letter, the value 
of the moment of transition in the second point of support to the right or to the 
left is indicated, etc. 
