76 Rules and Tables adapted 
H L, D O, parallel to base a Cc, and D K perpendicular to H L. 
Now let 2 denote half base or B Cc. 
h the height B H at centre stake. 
m : 1 rate of inclination of slopes. 
angle of inclination of sidelong ground. 
x the required horizontal side distance, or C D 
Then D K = 2 tang 6 
bie h+m—ez 
DK=> — m 
m 
b 
> thm—ez 
x tang } = 27 — 
m 
1 
Cara : + hm (=a) 
In Fig. III., in: which the sidelong inclination diverges 
from the centre stake in reference to the plane of the base, 
we obtain, in a similar manner, 
e. . BAN ill ei 
Side distance or x = § +hm ( I tang 0. 7 ) 
In Fig. IV. let the profile of the sidelong ground cross 
the half base, and occasion cutting and embankment on the 
same side of the centre stake. 
Here D K + HL = HL tang 6. tile 
DK —=HLtang}—KL—=zg, tangi—h 
cK x—b 
DK ae on, - 
z—b 
a. tang 8 — h = = 
m 
1 
z—=b—hm (a5 
1 — tang 6. m 
In Table No. I. I haye given values of men for the 
more ordinary slopes, and in Table No. II. similar values of 
: 
1 + tang 5. m 
