Proportional Representation. 31 



four were to be elected the number required would be the total 

 number of voters divided by five, plus one, and so on. The 

 calculation is a simple arithmetical one, and would have to be 

 done by the returning officer and his clerks. The lecturer then 

 stated that there had been four spoiled votes. One voter had 

 so evenly a balanced mind that he had put " i " after three 

 names ; he wanted three persons to have first place. Another 

 more remarkable one still was where a voter had marked a 

 name 2, another 3, another 4, but had omitted to mark " i." 

 These spoiled votes reduce the papers to 192, and the qualifying 

 number to 49. 



The persons who had been marked " i '' were then written 

 upon the blackboard as follows : — 



Lord Dufferin ... ... ... 113 



Professor Huxley ... ... ... i 



Mr. Justin M'Carthy ... ,.. 13 



Mr. Herbert Spencer ... ... 9 



Lord Tennyson ... ... .. 37 



Professor Tyndall ... ... ... i 



The lecturer said : — Lord Dufferin is duly elected, but his 

 Lordship only required 49 votes, whereas he has 113 papers. 

 He has, therefore, got a surplus of 64. We must take away, 

 therefore, 64 from his heap of 113. The question arises, which 

 64 ? Experience shows that it does not matter — the result in 

 the end will be practically the same. The 64 papers were 

 then taken from Lord DufFerin's " heap " and distributed with 

 the heaps indicated by the figure "2" placed upon them by the 

 voter. The result was that 7 votes were added to Professor 

 Huxley, 2 to Mr. M'Carthy, i to Mr. Spencer, 26 to Lord 

 Tennyson, and 28 to Professor Tyndall. The right hon. 

 gentleman said : — 



Lord Tennyson is in. He has got 63. He only, however, 

 wanted 49, so we will take from his heap 14, and add them 

 to the names marked "3." The result is that Mr. Huxley 

 gets I vote more, Mr. M'Carthy 2, Mr. Spencer 2, and Professor 

 Tyndall 9 more. That brings Professor Tyndall above the 



