238 UN NUOVO METODO PER DETERMINARE LA RESISTENZA DELL'ARIA 
Tavola II 
n= kb n= k,5 n= 4,6 
> n é H î n 
X x x E 
25,965 | —0,14606 32,582 | —0,18328f 39,199 | —0,22050 
12,635 | —0,14214 15,918 | —0,17908 19,201 | —0,21602 
I 
2 
S908 8,190 |—0,13812] 10,362 |—0,17477] 12,534 |—0,21143 
SAINT 5,970 | —0,13435f 7,587 | —017073] 9,204 | —0,2071 
DIST 4,738 |—0,13050f 6,021 | —0,16661 7,304 |—0,20269 
DON 3,747 | —0,12659] 4,808 | —0,16242f 5,869 |—0,19825 
120.9 3107 |-—0,122723] 4,009 | —0,15828f 4,911 |—0,19383 
CEI 2,638 |—0,11888f 3,420 |—0,15415f 4,203 |—0,18943 
220,6 2270 | —0,11542] 2,961 |—0,15013] 3,652 |—0,18545 
— 10 1,969 | —o,tn10gf 2,586 |—0,14580f 3,203 |—0,18052 
— MM 1,729 |—0,10738] 2,285 | —014183] 2,844 |—0,17629 
— 12 1,525 | —0,10356f 2,034 |—0,13775] 2,538 |—0,17198 
Laga 1,356 | —0,09976] 1,819 |—0,13367] 2,282 | —0,16760 
CDOT 1,192 | —0,09598f 1,618 |—0,12962] 2,044 |—0,16327 
— 15 1,082 |—0,09222f 1,477 | —0,12559f 1,872 |—0,15896 
— #6 0,973 | —0,08848Î 4,340 | —0,12159] 4,707 | —0,45471 
— 18 0,786 | —0,08098f 4,107 | —0,11355] 41,428 | —0,146412 
— 20 0,640 | —0,07354| 0,924 | —0,10558] 4,208 | —0,13762 
— 22 0,524 | —0,06629f 0,775 | —0,09781 1,028 |—0,12930 
— 25 0,375 | —0,05515] 0,592 | —0,08589f 0,809 |—0,11658 
— 30 0,189 | —0,03709] 0,362 | —0,06652f 0,535 | —0,09595 
— 85 0,075 | —0,01934 0,216 | —0,04748f 0,357 |—0,07565 
et) PE le 0,100 | —0,02880f 0,217 | —0,05573 
— 45 de sa - si 0,109 | —0,03616 
he 0 i e pa i 0,023 | —0,01701 
260 cL Se do) 2 ne Ur: 
