2/0 
UN NUOVO METODO PER DETERMINARE LA RESISTENZA DELL'ARIA 
Tavola II. 
= 
n= 5,0 n=5,1 n= 5,2 
| = F c F - F 
| X Xx X 
I 
— A 65,667 | —0,36938 72,278 | —0,40660 78,895 | —0,44382 
— 2 32,333 | —0,36378 35,616 | —0,40072 38,983 | —0,43766 
— 3 21,222 | —0,35803 23,394 | —0,39468 25,566 | —0,43133 
— 4 15,668 | —0,35263 17,282 | —0,38902 18,899 | —0,42540 
— 3 12,336 | —0,34713 13,624 | —0,38324 14,907 | —0,441935 
= 110 10,443, | —0,34156 14,177 | —0,37739 12,238 | —0,41321 
— .47 8,520 | —0,33603 9,423 | —0,37159 10,325 | —0,40714 
— 8 7,337 | —0,33053 8,120 | —0,36581 8,903 | —0,40108 
— 9 6,416 | —0,32518 7,106 | —0,36019 7,197 | —0,39520 
#19 5,671 | —0,31940 6,288 | —0,35412 6,905 | —0,38884 
— MI 5,065 | —0,34414 5,623 | =0,34856 6,179 | —0,38302 
— 12 4,564 | —0,30874 5,067 | —0,34293 5,573 | —0,37741 
— 13 4,134 | —0,30325 4,597 | —0,33716 9,060 | —0,374107 
— Ai 3,750 | —0,29783 4,176 | —0,33147 4,602 | —0,36511 
— 15 3,452 | —0,29245 3,846 —_0,32582 4,240 | —0,35920 
— 16 3,175 | —0,28713 3,542 | —0,32024 3,909 —0,3533% 
— 18 2,712 | —0,27640 3,033 | —0,30897 3,354 | —0,34154 
— 20 2,344 | —0,26577 2,628 | —0,29781 2,912 | —0,32985 
— 22 2,042 | —0,25541 2,296 | —0,28693 2,550 | -—0,31845 
Mt. 1,678 | —0,23952 1,895 | —0,27025 2,112 | —0,30097 
— 30 1,237 | —0,21369 1,410 | —0,24312 1,583 | —0,27256 
— 35 0,923 | —0,18834 1,064 | —0,21648 1,204 | —0,24464 
— 40 0,688 | —0,16341 0,806 | —0,19033 0,924 | —0,24725 
— 145 0,507 | —0,13895 0,606 | —0,16465 0,705 | —0,19035 
— 50 0,362 | —0,11501 0,447 | —0,13951 0,532 | —0,16401 
— 55 0,245 | —0,09158 0,318 | —0,41491 0,394 | —0,13824 
— 60 0,149 | —0,06869 0,212 | —0,09087 0,275 | —0,11306 
