Fig. X. 
Fig. X, 
Fig. XI. 
New Principles of Gardening. 
equal to the Radius of #@ and 77 common, and the Angles at 
zright-angled ; therefore the Side az is equal toz6. Q, Z. F. 
PROBLEM: Vitt. 
O divide any Line (as ab) in a given Proportion, as 
Cay ces oY 
Practice. ab, ac, being drawn atany Angle, draw the 
Right Line 6c, and draw ed parallel to it; therefore, as 
ba is to da, fois¢ a toea. 1G Bakes shi hoa: 
PROBLEM IX. 
‘O find a fourth Proportional (bd) to three given, Viz 
ae: ec i: ad: db. | 
Practice. Join ed, and draw cb parallel, and continue 
ad to 6, and dé is the fourth Proportional required ; for as 
ae isto ec, foisadtodd. O=.E.F | 
PROBLEM X. 
< O jind a third Proportional (nm) to two given, (z y> 
yx.) | 
_ Practice. Make 2 equal to 2 at any, Angle, cand. 
join y#. Continue 2% ” infinitely, and. from » draw the Par- 
rallel xm; mu is the third Proportional: For, as 2.9 is to Iitge 
foiszutonm. Q, E.F. | 
PR’O BL E M: Xi. 
PL) “tween two given Lines (ik, no) to find a mean Pro- 
) portion (ch.) | 
DerinitTion. A mean proportional Line, is fuch a Line, whofe 
Length being multiplied into it felf, its Produ& is equal to both 
the Products of the other two Lines between which it isa 
mean Proportional. 
PRAc- 
