Solutio. 

 Cnm excepto circulo a, reliqui omnes b, c, etc. per 

 a-tecedenlem et circLiios A, B, eodem plane modo determi- 

 nentur ac in Fig. i. erit etiam hic in genere ($. u.) pro 



radio c, 



4 A 2 B- b c (A - B — b) (A — B - c) 



j= c c [ A B (A — B) — b (A 2 -+- B )] 2 

 h- 2 A B (A - B) b c [A B (A - B) - b (A 2 h-B)] 2 

 h- A 2 B 2 (A — B) 2 b 2 . 

 Ponamus iam, legem afftimtam usque ad radium anteceden- 

 tem b qui eit (n — i)tus, veram effe, ita ut fit 



b = 4. **.!.--« _ (J. l6 .), 



et brevitatis gratia ponamus 



( i n - 3 ) 2 (A - B) 2 -+- 4 A B z= m, et A - B =_ C, 



ita ut fit 



b — 1_bc et A _ B _ 6 — ________ 



AB(A - B) — b(A 2 -t-B 2 ) = 

 ^ (4- n 2 C 2 — 12 rj C 2 -+- 5 C 2 — 4 A B). 

 Unde aequatione in — 7 ^~r ducTa nancifcimur 

 i6( n— - 3 ) 2 ABC 2 c(C — c) = 



c c [ 4 n 2 C 2 — 1 2 n C 2 -4- 5 C 2 — 4 A B f 

 + 8ABCc[ 4 rC 2 -i2nC 2 + 5C 2 -4AB] 

 + i6A 2 B 2 C 2 , five 

 cct(2n-i) 2 C 2 H-4AB][(2n-5) 2 C 2 -+4AB] 

 ■-8ABCc[(4n 2 -i2nH-i3)C 2 -+-.4AB] 



h-i6A 2 B C 2 =o. 



Eft 



